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arpitm08
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Fluids at rest problem help!
How much force does it take to hold 0.5 m^3 of medium density (specific gravity = 0.77) wood under water?
density of wood is 770 kg/m^3.
Fb is the force of buoyancy that pushes the wood up.
F-Fb = mg
F-9.81(0.5)(1000) = 770*0.5 (9.81)
F = 8682 N
I don't know what the answer is, but i don't think that this is right. It might be i don't know. Could someone help.
Homework Statement
How much force does it take to hold 0.5 m^3 of medium density (specific gravity = 0.77) wood under water?
The Attempt at a Solution
density of wood is 770 kg/m^3.
Fb is the force of buoyancy that pushes the wood up.
F-Fb = mg
F-9.81(0.5)(1000) = 770*0.5 (9.81)
F = 8682 N
I don't know what the answer is, but i don't think that this is right. It might be i don't know. Could someone help.