- #1
Nik
- 4
- 0
Hi, today I was writing my Identities final test and got stuck on one question which I couldn't solve.
The question was: If [tex]sinB=-\frac{5}{13}[/tex] find the exact value of [tex]tan2B[/tex].
I've got this far, correct me if I went wrong anywhere: [tex]tan2B=\frac{sin2B}{cos2B}=\frac{2sinBcosB}{2cos^2B-1}[/tex]
Then, when I tryied to solve further I came to a dead end, even though I tried many different ways.
Thanx in advance!
The question was: If [tex]sinB=-\frac{5}{13}[/tex] find the exact value of [tex]tan2B[/tex].
I've got this far, correct me if I went wrong anywhere: [tex]tan2B=\frac{sin2B}{cos2B}=\frac{2sinBcosB}{2cos^2B-1}[/tex]
Then, when I tryied to solve further I came to a dead end, even though I tried many different ways.
Thanx in advance!