- Thread starter
- #1

Solve: dy/dx + y^2 = y.

after taking partial fractions, i simplified this to: (1/y + 1/ (1-y) ) dy = dx

and i integrated that to ln (mod) y + ln (mod) (1-y) = x + c

how do i transpose for y here? when i take exponents on either side i get y + 1 - y = e^x + c

which works out to 0= e^x + c.

This doesn't seem right... is it? what's wrong??