- Thread starter
- #1
Petrus
Well-known member
- Feb 21, 2013
- 739
Hello MHB,
\(\displaystyle (x^2+1)y'-2xy=x^2+1\) if \(\displaystyle y(1)=\frac{\pi}{2}\)
What I have done:
Divide evrything by \(\displaystyle x^2+1\) and we got
\(\displaystyle y'-\frac{2xy}{x^2+1}=1\)
we got the integer factor as \(\displaystyle e^{^-\int\frac{2x}{x^2+1}}= e^{-ln(x^2+1)}\)
Now I get
\(\displaystyle (e^{-ln(x^2+1)}y)'=e^{-ln(x^2+1)}\)
and this lead me to something wrong, I am doing something wrong or?
Regards,
\(\displaystyle |\pi\rangle\)
\(\displaystyle (x^2+1)y'-2xy=x^2+1\) if \(\displaystyle y(1)=\frac{\pi}{2}\)
What I have done:
Divide evrything by \(\displaystyle x^2+1\) and we got
\(\displaystyle y'-\frac{2xy}{x^2+1}=1\)
we got the integer factor as \(\displaystyle e^{^-\int\frac{2x}{x^2+1}}= e^{-ln(x^2+1)}\)
Now I get
\(\displaystyle (e^{-ln(x^2+1)}y)'=e^{-ln(x^2+1)}\)
and this lead me to something wrong, I am doing something wrong or?
Regards,
\(\displaystyle |\pi\rangle\)