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#### Petrus

##### Well-known member

- Feb 21, 2013

- 739

\(\displaystyle (x^2+1)y'-2xy=x^2+1\) if \(\displaystyle y(1)=\frac{\pi}{2}\)

What I have done:

Divide evrything by \(\displaystyle x^2+1\) and we got

\(\displaystyle y'-\frac{2xy}{x^2+1}=1\)

we got the integer factor as \(\displaystyle e^{^-\int\frac{2x}{x^2+1}}= e^{-ln(x^2+1)}\)

Now I get

\(\displaystyle (e^{-ln(x^2+1)}y)'=e^{-ln(x^2+1)}\)

and this lead me to something wrong, I am doing something wrong or?

Regards,

\(\displaystyle |\pi\rangle\)