- #1
Jrlinton
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Homework Statement
How much work does the force do?
As the object moved, friction with a coefficient of 0.2 also acted upon it. What is its final speed if it started at rest?
Homework Equations
The Attempt at a Solution
So the work done from 0.5m to 2.0 m was easy enought to find as I just used the graph to find the area between the data and the x-axis coming up with 27.5J
I calculated the work of friction (-u*m*g*d) -0.2*5kg*9.81m/s/s*1.5m= -14.715 J. I subtracted this from the 27.5 joules found earlier to get 12.785 J. Set 12.785=0.5*m*v^2=(0.5)(5kg)(v^2) and found v to be 2.26 m/s. This was incorrect...[/B]