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The height of an object in meters after t seconds is given by \(\displaystyle H(t) = 152t - 16t^2\).

a) When does it hit the ground?

My answer: t(152 - 16t) = 0 which means t = 0, \(\displaystyle t = \frac{152}{16}\)

b) What is the velocity when it hits?

152 - 304 = -152 m/s

Is this correct?