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Weightofananvil
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Homework Statement
The question asks
the current through a 2uF capacitor is show. sketch the capacitor voltage Vc between t = 0ms give that the voltage at t=0ms is 0V. Your graph must be correctly scaled with numerical values.
There is a graph included showing a current rise for 0-2 milliseconds. 0 current for 2-4 milliseconds negative current for 3 milliseconds.
The Attempt at a Solution
I understand this question is asking for the difference between graphing Ic and Vc. I have the graph drawn and understand the difference between Ic and Vc in a charging and discharging circuit.
Now, I must convert my current values into voltage values and then add it to my graph. This is where I am stuck.
I know that:
Vc=Vo(E^-t/rc) and ic =-Vo/R(E^-t/rc) are used when a capacitor is charging and discharging.
both of those have voltages in the formula, so I can't use them.
I know Q=CV
I also know coulomb is 1s/A
can I change that to be A= Δ Q/Δ T ??
and rearrange it to Q= Δ A x Δ t ??
I can't figure out how to get the current to voltage!