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#### Jipsonburger

##### New member

- Aug 5, 2012

- 2

Hence i have put a glass on an axis and modelled an equation for the top half of the glass...

\(\displaystyle f(x)= -0.00393x^4+0.0843x^3-0.693x^2+2.198x+1.246\)

I know how to find the volume of the whole glass (using solids of revolution) which is 188mL (188cm^3), but i am unable to find a method for working out the volume when its tipped on its side and filled up (i.e) the region between the glass and the line \(\displaystyle g(x)=2.46\).

So in effect my question is:

"How do i work out the volume of the liquid that can be poured into this glass when it is placed on its side, using solids of revolution?

If anyone could shed some light on the issue it would be greatly appreciated =) Thanks in advance =)