- #1
dnt
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- 0
ln (x+1) = x-3
i know ln is log base e so the equation becomes:
e^(x-3) = x + 1
and i can rearrange using algebra to get:
e^x = e^3(x+1)
but now I am stuck...how can i separate the x's to solve for it?
thanks.
i know ln is log base e so the equation becomes:
e^(x-3) = x + 1
and i can rearrange using algebra to get:
e^x = e^3(x+1)
but now I am stuck...how can i separate the x's to solve for it?
thanks.