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Westin
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Homework Statement
A mass of 0.36kg hangs motionless from a vertical spring whose length is 0.8m and whose unstretched length is 0.51m. Next, the mass is pulled down to where the spring has a length of 1.09m and given an initial speed upwards of 1.2m[PLAIN]https://s3.lite.msu.edu/adm/jsMath/fonts/cmmi10/alpha/144/char3D.pngs. What is the maximum length of the spring during the motion that follows?
Maximum length=
Homework Equations
F = k*y
1/2*k*A^2[/B]
The Attempt at a Solution
k = F/y = m*g/y = 0.36kg*9.8m/s^2/(0.8m - 0.51) = 12.17793N/m
Energy is conserved
Let A be the maximum displacement
So 1/2*k*A^2 = 1/2*k*(1.09 - 0.51)^2 + 1/2*m*v^2
so A = sqrt((1.09 - 0.51)^2 + m/k*v^2) = sqrt((1.09 -0.51)^2 + 0.36/12.18*1.2^2) = 0.5974m
So the length will be 0.51 + 0.5974m = 1.11m
I only have one attempt wrong, Cant find the error..[/B]
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