Finding the log by using the proportional table

[cbarker1]

Logarithms​

N	0	1	2
293	46687	46702	46716
294	46850	46835	46864
295	46982	46997	47012

Prop. Pts​

1	1.6
2	3.2
3	4.8
4	6.4
5	8.0
6	9.6
7	11.2
8	12.8
9	14.4

Find the value of $\log\left({29517}\right)$
Work:
4+$\log\left({2.9517}\right)$

Thanks for your help

 

[I like Serena]

Logarithms​

N	0	1	2
293	46687	46702	46716
294	46850	46835	46864
295	46982	46997	47012

Prop. Pts​

1	1.6
2	3.2
3	4.8
4	6.4
5	8.0
6	9.6
7	11.2
8	12.8
9	14.4

Find the value of $\log\left({29517}\right)$
Work:
4+$\log\left({2.9517}\right)$

Thanks for your help

Hi Cbarker1,

To find $\log(2.9517)$, we look up row $295$ in the table.
Then we pick the column with 1, where we find $46997$.
For the last digit we consult the 2nd table, where entry $7$ has $11.2$, which we add for a total of $47008.2$.

In the table the decimal points have been left out, which means we need to read this as $0.470082$.
Add the $4$ you found for a total of $4.470082$.

My calculator says $4.470072$.
Presumably the small discrepancy is an approximation error due to the use of the second table.