- #1
Jd303
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If the total energy stored in the circuit below is 190 mJ, what is the value of L?
IS = 2 A
R1 = 250 Ω : R2 = 38 Ω
C = 41 µF
Give your answer to the nearest whole number, in mH (I have attached the diagram)
I first try to find the equivalent impedence knowing that the impedence of an inductor is jωL and the impedence of a capacitor is -j/(ωC)
I try to do this so as I can find Vs and hence using the formula:
E = (CV^2 + LI^2)/2
I would be able to find the value of L
However I have too many unknowns to be able to find the equivalent impedance, so how do i go about this question? Any help would be greatly appreciated I am really stuck. Thanks!
IS = 2 A
R1 = 250 Ω : R2 = 38 Ω
C = 41 µF
Give your answer to the nearest whole number, in mH (I have attached the diagram)
I first try to find the equivalent impedence knowing that the impedence of an inductor is jωL and the impedence of a capacitor is -j/(ωC)
I try to do this so as I can find Vs and hence using the formula:
E = (CV^2 + LI^2)/2
I would be able to find the value of L
However I have too many unknowns to be able to find the equivalent impedance, so how do i go about this question? Any help would be greatly appreciated I am really stuck. Thanks!