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- #1

^{2}/

_{3. }Then I am looking to find the midpoints, of the line, which are [

^{4}/

_{2}, -

^{2}/

_{2}]. I have then calculated the perpendicular of the line AB, which had a gradient -

^{2}/

_{3.}The perdendicular gradient is

^{2}/

_{3. }

I am then trying to find the equation of the line. This is what I have completed.

Bisector of line AB

b

_{AB }: y - [-

^{2}/

_{2}] =

^{2}/

_{3}(x -

^{4}/

_{2}) Implies y = 2/3x - 4/2 - 2/2 =

**y =**

^{2}/_{3}x -^{6}/_{2 }If this is the correct equation then I am at a loss because I am lead to believe that the parametric equation;

y = (3x - 8) / (2)

should give the same answer?

The parametric equation gives; y = (3(

^{4}/

_{2}) - 8) / (2) = -

^{2}/

_{2 }I am quite OK with this because the midpoint is the same y value, so I think I got that right, but;

**y =**

^{2}/_{3}x -^{6}/_{2}Should give the same answer but to me does not?

y = 2/3(

^{4}/

_{2}) -

^{6}/

_{2}= - 1

^{2}/

_{3 }which is - 1.67 (2dp)

The solutions are close but not exact, so I must be making a mistake somewhere I think?

Kind regards

Casio