Finding the displacement under a curve.

[kimberley511]

1. What is the displacement between t= 0 s and t= 7 s?The "area' under the curve, between the two times is the displacement. The "area" is the area enclosed by the curve and the time axis (v=0 line). Those parts of the curve with negative velocity contribute negative area and those with positive velocity contribute positive area.
Between t=0 s and 7 s,

Δx =

Homework Equations

Area of Rectangle: (l*w)
Area of Trapezoid: (1/2 b (h1+h2))
Area of Triangle: (1/2bh)
3. Rectangle: 1.5(-380)= -570
Trapezoid:1/2*3*(-380+-280)=-825
Triangle: 1/2*1.5*280=-420

delta x = -(570+825+420)= -1815 ...this was my attempt and it was wrong. I don't know what I am doing wrong please help

Homework Statement

Homework Equations

The Attempt at a Solution

 

[davo789]

Could you elaborate on how you got your answer for delta x?

 

[kimberley511]

I used the points for t-0 and t-7 and came up with the three shapes on the graph..(the rectangle the trapezoid and the triangle) and then solved for their area under the curve and then combined.

I don't have a scanner to post the graph that I drew the shapes on.

 

[SteamKing]

You should be calculating the area between the curve and the horizontal axis where
v = 0.

 

[rwisz]

I would first clarify what type of curve we are dealing with. Is it a position vs. time curve or a velocity vs. time curve? This information is crucial in determining the displacement.

If it is a position vs. time curve, then the displacement can be found by calculating the area under the curve between t=0 s and t=7 s. This can be done by breaking the area into smaller shapes, such as rectangles, trapezoids, and triangles, and then adding the areas together.

If it is a velocity vs. time curve, then the displacement can be found by calculating the area between the curve and the time axis. This area represents the change in position over time, or displacement. Again, this can be done by breaking the area into smaller shapes and adding them together.

In this case, since the given values are negative, it is important to pay attention to the signs of the areas. A negative area would contribute to a negative displacement and a positive area would contribute to a positive displacement.

Without further information about the curve, I cannot provide a specific solution. However, I would recommend breaking the area into smaller shapes and carefully considering the signs of each area to correctly calculate the displacement.