You would take the midpoint of opposite vertexes. Take the coordinates of A and C, the midpoint of that, then the midpoint of D to B. That is if the plane is say a square with ABCD, listed in order all around. This is if only it is a square. If a parallelogram, I think you take the midpoint A to D, and B to C. I dont really know if my answer is correct, I have geometry teacher that seems sketchy lol.
Very quickly, I want to thank the help I have received. I am still working out the calculations regarding how I am applying it and so far I am having some problems but it may just be a simple error.
Regardless, thanks for the help and as soon as I have something more concrete to post I will definitely follow up as a courtesy for your help.
``````````````````````````````````````````````````````````````````````````
1)
I used the formula on the wikipedia link provided by ILikeSerena.
Assuming this is the formula that I am genuinely looking for, the two coordinates that I produce by using this formula is not the intersection of the two lines.
2)
And I am still unsure of how to test the revised formula ILikeSerena provided.
3)
I am unsure if the formula provided by the Dr. Math link applies because the formula is based on a three dimensional line.
The two lines are on the same plane (x,y) so a z-coordinate at this point is unnecessary.
```````````````````````````````````````````
Question:
Can anyone provide:
a)
a line with the xy-coordinates of two points on that line
b)
a second line with the xy-coordinates of two points on that line and on the same plane as the first line
c)
and demonstrate the use of a formula using those two lines to produce the intersection of the xy-coordinates of the point at which the two lines intersect?
I have just created an excel sheet with 2 lines, using the 2-dimensional formula (from wiki):
As you can see, the result matches the intersection point.
The formula I gave is the most generic, which is for m dimensions and for 2 or more lines.
Based on your opening post, I thought you were asking for that.
After your current comment it appears that you don't need it.