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- Thread starter Cbarker1
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- Thread starter
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- Apr 13, 2013

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$f(x)=tan(2x)$ is continuous everywhere except the vertical asymptotes. To find the vertical asymptotes,we set the denominator $0$.So,as $tan(2x)=\frac{sin(2x)}{cos(2x)}$,we set $cos(2x)=0 \Rightarrow x=\pm \frac{\pi}{4},\pm \frac{3\pi}{4},.....$I need some help find some continuous intervals for $f(x)=tan(2x)$. I know there are vertical asympotes when x=pi/4+2*pi*n for positive integers.

Thank you for your help.

CBarker1

Therefore,$tan(2x)$ is continuous everywhere except at $x$,where $x=\frac{n \pi}{4}$,where $n$ odd numbers.

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