- #1
rileyjah
- 6
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Spring problem!
A 1.60 kg block hangs from a spring. If a 400 g body is hung from the block, the spring is stretched 2.00 cm farther. What is the spring constant?
Fsp=-kdeltas
(2.0Kg)(9.8)/(0.02)=k
k-980 N/m... which is wrong
So I am assuming that at equilibrium with m1 x=0, and when the second mass is added the total displacement is delta s=0.02 m - what am I missing?
Homework Statement
A 1.60 kg block hangs from a spring. If a 400 g body is hung from the block, the spring is stretched 2.00 cm farther. What is the spring constant?
Homework Equations
Fsp=-kdeltas
The Attempt at a Solution
(2.0Kg)(9.8)/(0.02)=k
k-980 N/m... which is wrong
So I am assuming that at equilibrium with m1 x=0, and when the second mass is added the total displacement is delta s=0.02 m - what am I missing?