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thewestbrew
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Homework Statement
A 42.5kg person is going down a hill sloped at 42.0 degrees.
The coefficient of kinetic friction between the snow and skis is 0.180.
How fast is the skier going 4.56 seconds after starting from rest?
Homework Equations
ffkmax=coefficient of kinetic friction*Normal Force
fnet=mass*a
mg*cos(42)
mg*sin(42)
The Attempt at a Solution
mg=425
mg*cos(42)=315.8
Fn=mg*cos
ffkmax=(.18)(315.8)=56.8
ffkmax=netforce (no idea from this point on)
fnet=ma 56.8/m=a 56.8N/42.5kg= 1.33ms/^2
V=Vo+a*t
V=(0)+(1.33)(4.56)=6.06m/s