Finding line impedance of an AC circuit

In summary, the conversation discusses the speaker's attempts to analyze a circuit in a lab using both ideal and experimental analysis. They mention using Multisim software and a function generator to produce a sine wave with specific parameters, as well as using a lab manual to calculate line impedance. However, the speaker is confused and not getting accurate results, possibly due to inaccurate time measurements or a transient response in the circuit. They also mention the concept of power factor and compensating reactance to achieve maximum real power. Despite their attempts to analyze the circuit, they are still unsure about the accuracy of their measurements and the values they are obtaining.
  • #1
byte
4
0
So I've been trying to figure out what I'm doing wrong regarding a theoretical aspect of this lab. I've used both ideal analysis and experimental analysis and can't figure out if I'm doing this right.

The circuit is shown produced in Multisim below:

N5d7v.png


The function generator produces a sine wave of 10 Vp, 1 kHz, 0 V DC offset

The corresponding OSCOPE window is shown below with the peak values indicated and the time delay given:

H1Q63.png


My lab manual says that the line impedance is given by this equation:

ELCcD.png


It gives the derivation of this formula based on a similar circuit where Z_load is the load measured and Z_line is represented by the line impedance.

So given:
Z_L = 100
V_S = 9.999 V
V_L = 9.694 V
dt = 30e-6 s
ω = 2πf = 2 * pi * 1000

Input into MATLAB:

>> 100*((9.999/9.694)*exp(i*2*pi*1000*30e-6)-1)

ans =

1.3193 +19.3277i

This does not seem to agree with what I know about the ideal line transmission! Why does this happen?

From the answer:
R_line = 1.3193 ohm =/= 1 ohm (but close enough?)
X_line = 19.3277 = jwL --> 19.3277/1000 = L = 1.93 mH =/= 3.3 mH


Keep in mind this is all done in Multisim, which I thought is supposed to be pretty close if not actually ideal measurements. I'm not sure what I'm doing wrong, or if indeed these are the correct values that I'm supposed to obtain. The lab manual mentions compensating reactance which is the negative X_line to correct the power factor to 1.

Power tends to go over my head so I'd be most grateful if anyone could clear up the problem I'm having. Needless to say that since I'm confused in the ideal, theoretical case, I'm not getting anywhere in the experiments where I utilize these equations.



I analyzed the circuit on pen and paper through a voltage divider:

V_L = 10e^(j0) [ (100)/(100+j3.3) ] = 10e^(j0) * 100 / (101.05e^(j*1.87))
V_L = 9.896e^(j*-1.87)

Not getting anywhere with that either.
 
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  • #2
byte said:
This does not seem to agree with what I know about the ideal line transmission! Why does this happen?

From the answer:
R_line = 1.3193 ohm =/= 1 ohm (but close enough?)
X_line = 19.3277 = jwL --> 19.3277/1000 = L = 1.93 mH =/= 3.3 mH
It could be that your time measurements from the "scope" are not as accurate as they could be. I see that you're displaying about 5 cycles of the waveform. Why not adjust the timebase so that you see only a single cycle of Vs, and then take your Δt measurements between the zero crossings of each signal. This should be more accurate than trying to locate the peaks of the sinewaves.
Keep in mind this is all done in Multisim, which I thought is supposed to be pretty close if not actually ideal measurements. I'm not sure what I'm doing wrong, or if indeed these are the correct values that I'm supposed to obtain. The lab manual mentions compensating reactance which is the negative X_line to correct the power factor to 1.

Power tends to go over my head so I'd be most grateful if anyone could clear up the problem I'm having. Needless to say that since I'm confused in the ideal, theoretical case, I'm not getting anywhere in the experiments where I utilize these equations.
The power factor is the cosine of the angle that is the difference in phase between the current waveform and voltage waveform for the signal. If you "compensate" the line reactance by adding its negative in series with the line then the net reactance becomes zero and thus the phase difference between I and V becomes zero. When I and V are in phase you transfer maximum real power.
I analyzed the circuit on pen and paper through a voltage divider:

V_L = 10e^(j0) [ (100)/(100+j3.3) ] = 10e^(j0) * 100 / (101.05e^(j*1.87))
V_L = 9.896e^(j*-1.87)

Not getting anywhere with that either.
What were you trying to determine?
 
  • #3
gneill said:
It could be that your time measurements from the "scope" are not as accurate as they could be. I see that you're displaying about 5 cycles of the waveform. Why not adjust the timebase so that you see only a single cycle of Vs, and then take your Δt measurements between the zero crossings of each signal. This should be more accurate than trying to locate the peaks of the sinewaves.

Well, Multisim allows me to set a cursor to the peak value--the values that I have in the oscope are not values that I have manually selected to be peaks. Therefore, they should be accurate. I've taken dt at the zero crossings and have noticed no difference, although during labs I'll take dt at zero crossings because it's easier to locate.

There seems to be a sort of transient response in the first few cycles or so. Initially I was taking my peak values at the very beginning of my oscope reading and noticed I was getting slightly different values between the first few peaks... Off by a few mV but sometimes dt was also off and that was troubling.

Now, I let the circuit run for a few seconds, letting it reach what I assume to be steady state before taking the measurements at the end of the reading. This seems to eliminate the inconsistent values I was getting.

gneill said:
The power factor is the cosine of the angle that is the difference in phase between the current waveform and voltage waveform for the signal. If you "compensate" the line reactance by adding its negative in series with the line then the net reactance becomes zero and thus the phase difference between I and V becomes zero. When I and V are in phase you transfer maximum real power.

Yep! I noticed that when compensating the line reactance the pf goes to 1 and a maximum voltage load is achieved (and therefore maximum real power).

I understand that. What I don't understand is that if the measurements I'm taking to find Z_line are accurate and ideal, shouldn't Z_line = R_line + jwL_line = 1 + j3.3 (for 1kHz for example)? Instead there seems to be some confounding factor that does not give that ideal value, unless I'm misunderstanding what I'm calculating in Z_line.

gneill said:
What were you trying to determine?

I was trying to determine the power absorbed by the load at 1 kHz... Using a voltage divider I found V_L, V_S is given (as 10e^(j0)) and dt is a result of the difference of phase angles. It occurs to me, though, that I did not find the current phase angle and therefore could not calculate dt correctly.Update: My mistake has been trivial. I forgot to remember that, when determining X_L = jwL, w = 2*pi*f... Now, all of my values make sense and it would seem I've been doing the rest of this assignment correctly.
 
Last edited:
  • #4
It's possible that Multisim's timesteps for the curves are such that there will be some inaccuracies in the values ("discretization error"). This will be particularly true for horizontal or vertical parts of the curves where the "steps" are maximized along those directions. Does Multisim allow you to set a maximum timestep size?

Also check that Multisim isn't adding a default value of series resistance to its inductors. Some simulators do this.

I suspect that the Δt value should be closer to 32 μs.
 
  • #5


As a scientist, it is important to thoroughly analyze and understand the theoretical concepts before conducting experiments. In this case, it seems that there may be some confusion in the derivation of the line impedance formula. It is important to double check the equations and make sure they are accurate before using them for analysis.

Additionally, when conducting experiments in a simulation program like Multisim, it is important to ensure that the circuit is set up correctly and all the parameters are accurately inputted. Small errors in the setup or input values can greatly affect the results.

In terms of the discrepancy between the theoretical and experimental values, it could be due to various factors such as the accuracy of the equipment used, the precision of the measurements taken, and the assumptions made in the theoretical analysis. It may be helpful to consult with a lab instructor or peer to troubleshoot and identify any potential sources of error.

Furthermore, the concept of compensating reactance to correct for power factor is a complex one and may require further research and understanding. It is important to fully grasp the concept and its implications before attempting to apply it in experiments.

In conclusion, it is crucial to carefully review and understand the theoretical concepts before conducting experiments. It may also be helpful to consult with others and seek guidance when encountering discrepancies between theoretical and experimental results.
 

Related to Finding line impedance of an AC circuit

1. How do you calculate line impedance of an AC circuit?

The line impedance of an AC circuit can be calculated using the formula Z = R + jX, where R is the resistance and X is the reactance. This can also be represented as a complex number, Z = |Z|∠θ, where |Z| is the magnitude of the impedance and θ is the phase angle.

2. What factors affect the line impedance of an AC circuit?

The line impedance of an AC circuit is affected by the length and cross-sectional area of the wire, the type of material used, the frequency of the AC signal, and any external components such as transformers or filters.

3. How does line impedance impact the performance of an AC circuit?

The line impedance of an AC circuit can significantly impact its performance. A high line impedance can cause voltage drops and power losses, leading to decreased efficiency and potentially affecting the functionality of the circuit. It is important to minimize line impedance to ensure optimal performance.

4. What is the difference between line impedance and load impedance?

Line impedance refers to the impedance of the wire or transmission line used to carry the AC signal, while load impedance refers to the impedance of the device or load connected to the circuit. Line impedance is mainly affected by the physical characteristics of the wire, while load impedance is determined by the components and design of the device.

5. How can line impedance be measured or tested in an AC circuit?

Line impedance can be measured using specialized equipment such as an impedance analyzer or a multimeter. It can also be calculated using known values of resistance, reactance, and frequency. Additionally, simulations can be used to estimate line impedance in a circuit design before testing with physical components.

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