- #1
joej24
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Homework Statement
Attached below
Homework Equations
Emf = - [itex]\Delta[/itex][itex]\Phi[/itex] / [itex]\Delta[/itex]t
emf = vBl; motional emf
The Attempt at a Solution
In the two attached files, there are problems that ask for the direction of the induced current.
I understand that the induced current flows in the direction that opposes the magnetic flux that created it.
In the first file, [itex]\Delta[/itex][itex]\Phi[/itex] is negative because flux (BAcos[itex]\theta[/itex]) was smaller in the 2nd case than in the 1st. cos 0 > cos 60.
The opposite direction of the induced current is up because [itex]\Delta[/itex][itex]\Phi[/itex] is negative
But, how would I find out the direction of the current?
FB = I l B sin[itex]\theta[/itex]
We only know that we need magnetic flux and magnetic field to point upwards. Without the direction of FB, how can I use the right hand rule to find the direction of the induced current?
I have the same problem with the problem shown in the second file.
emf = vB l (memorized equation)
We then need magnetic flux out of the page and the magnetic field to do so as well.
Also, is motional emf the same as induced emf?