Finding Coordinates of A and B in an Equilateral Triangle

[ehild]

I just want to point out that this problem has two possible solutions: I only saw one posted. You can see this by drawing lines to represent the possible points for A and B. In other words, ##(a, 11)## is somewhere on the line ##y = 11##. The point ##(b, 37)## is somewhere on the line ##y = 37##.

Yes, but the given picture suggest position in the first quadrant.

ehild

 

[ehild]

I just want to point out that this problem has two possible solutions: I only saw one posted. You can see this by drawing lines to represent the possible points for A and B. In other words, ##(a, 11)## is somewhere on the line ##y = 11##. The point ##(b, 37)## is somewhere on the line ##y = 37##.

Yes, but the given picture suggest position in the first quadrant.

ehild

 

[sankalpmittal]

Yes, but the given picture suggest position in the first quadrant.

ehild

So Coni's method will offer one solution as z₁/z₂=e^iπ/3.

Other will depend on quadrants due to the term e^iπ/3 (sign of angle). That won't matter as it is first quadrant related.