Finding constants in exponential functions

In summary, the population of a country was estimated to be 9.77 million in 2010, but was estimated to be 8.23 million in 2000.
  • #1
LivvyS
19
0

Homework Statement


In 2000 the population of a country was estimated to be 8.23 million. In 2010 the population was 9.77 million.

Assume that the number of people P(t) in millions at time t (in years since 2000) is modeled by the exponential growth function.

P(t) = Aekt

Find P(t) giving the two constants in it to 2 significant figures.

Homework Equations


P(t) = Aekt

The Attempt at a Solution



P(0) = 8.23x106 so Ae0k= 8.23x106

P(10) = 9.77x106 so Ae10k= 9.77x106Divide to eliminate A:
Ae0k= 8.23x106 / Ae10k= 9.77x106 = e0k-10k= 8.23x106 / 9.77x106 = e-10 k = 8.23x106 / 9.77x106
(I am not certain that this step is right)

-10k = ln 8.23x106 / 9.77x106

k = 0.01917945693

To find A:
Ae10k= 9.77x106
Ae10*0.01917945693= 9.77x106
A = 9.77x106 / e10*0.01917945693 = 8064904.714

These values for k and A seem to produce 9.77x106 when 10 (years) is plugged into the function, however I can't seem to produce 8.23x106 at 0 years since 2000 and I can't seem to see why, any help would be much appreciated!
 
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  • #2
LivvyS said:

Homework Statement


In 2000 the population of a country was estimated to be 8.23 million. In 2010 the population was 9.77 million.

Assume that the number of people P(t) in millions at time t (in years since 2000) is modeled by the exponential growth function.

P(t) = Aekt

Find P(t) giving the two constants in it to 2 significant figures.

Homework Equations


P(t) = Aekt

The Attempt at a Solution



P(0) = 8.23x106 so Ae0k= 8.23x106

P(10) = 9.77x106 so Ae10k= 9.77x106


Divide to eliminate A:
Ae0k= 8.23x106 / Ae10k= 9.77x106 = e0k-10k= 8.23x106 / 9.77x106 = e-10 k = 8.23x106 / 9.77x106

(I am not certain that this step is right)

-10k = ln 8.23x106 / 9.77x106

k = 0.01917945693

To find A:
Ae10k= 9.77x106
Ae10*0.01917945693= 9.77x106
A = 9.77x106 / e10*0.01917945693 = 8064904.714

These values for k and A seem to produce 9.77x106 when 10 (years) is plugged into the function, however I can't seem to produce 8.23x106 at 0 years since 2000 and I can't seem to see why, any help would be much appreciated!

The trick is to remember what the value of the exponential is when t = 0. What is exp(0)? If you know what the population is at t=0, how is this related to A?
 
  • #3
Thanks for the reply!

So if the exponent of e is 0 then P(0) = A*1 so A = 8.23x106
But if this were true than the answer for a I calculated cannot be right, if so could you give me a clue as to what's wrong with it?
 
  • #4
Method is right, something goes wrong from -10k = ln 8.23x106 / 9.77x106 ⇒k = 0.01917945693

(you typed ... instead of ...)
 
  • #5
LivvyS said:

Homework Statement


In 2000 the population of a country was estimated to be 8.23 million. In 2010 the population was 9.77 million.

Assume that the number of people P(t) in millions at time t (in years since 2000) is modeled by the exponential growth function.

P(t) = Aekt

Find P(t) giving the two constants in it to 2 significant figures.

Homework Equations


P(t) = Aekt

The Attempt at a Solution



P(0) = 8.23x106 so Ae0k= 8.23x106

P(10) = 9.77x106 so Ae10k= 9.77x106Divide to eliminate A:
Ae0k= 8.23x106 / Ae10k= 9.77x106 = e0k-10k= 8.23x106 / 9.77x106 = e-10 k = 8.23x106 / 9.77x106
(I am not certain that this step is right)

-10k = ln 8.23x106 / 9.77x106

k = 0.01917945693

To find A:
Ae10k= 9.77x106
Ae10*0.01917945693= 9.77x106
A = 9.77x106 / e10*0.01917945693 = 8064904.714

These values for k and A seem to produce 9.77x106 when 10 (years) is plugged into the function, however I can't seem to produce 8.23x106 at 0 years since 2000 and I can't seem to see why, any help would be much appreciated!

It is much, much easier just to work in units of millions, so that your two equations are
[tex] A = 8.23 \; \text{and}\; A e^{10 k} = 9.77[/tex]
By choosing those new units you eliminate a lot of the clutter and make it much easier to see what is happening (and to find errors). You can always convert to other units later, after you have solved the problem.
 
  • #6
Poster had everything OK until he typed 997 instead of 977
 

Related to Finding constants in exponential functions

1. What is an exponential function?

An exponential function is a mathematical function in which the independent variable appears in the exponent. It can be written in the form of f(x) = ab^x, where a and b are constants and x is the independent variable. The graph of an exponential function is a curve that either increases or decreases rapidly.

2. How do you find the constant in an exponential function?

To find the constant in an exponential function, you need to have two points on the graph of the function. Then, you can use the formula y = ab^x to solve for the constant a, by plugging in the two points and solving for a. Once you have a, you can find the constant b by taking the ratio of the y-values of the two points and raising it to the power of 1 over the difference of the x-values.

3. What is the significance of finding constants in exponential functions?

Finding constants in exponential functions is important because it helps us understand the behavior of the function. The constants a and b determine the growth or decay rate of the function, and knowing these values can help us make predictions and solve real-world problems.

4. Can you find the constants in an exponential function if you only know one point on the graph?

No, you cannot find the constants in an exponential function if you only know one point on the graph. This is because there are an infinite number of exponential functions that pass through a single point, and without a second point, we cannot uniquely determine the values of a and b.

5. Are there any real-life applications of finding constants in exponential functions?

Yes, there are many real-life applications of finding constants in exponential functions. For example, in finance, the compound interest formula is an exponential function that can help us calculate the growth of investments over time. In biology, exponential growth and decay can be used to model population growth or the decay of radioactive substances. In physics, exponential functions can describe the behavior of radioactive decay and the growth of bacterial colonies.

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