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#### karush

##### Well-known member

- Jan 31, 2012

- 2,716

Relative maximum (3,3) Relative minimum (5,1) Inflection point (4,2)

I approached this by using the f'(x)= a(3)(x^2)+b(2)(x)+c with the min and max

and f''(x)=6x+2b for inflection pt to get

$27a +6b + c =3$

$75a+10b+c=1$

$24a + 2b = 2$

Then I ran it thru a system equation solver but did not get the coefficeints needed that are in the answer which is ?

$\frac{1}{2}x^3-6x^2+\frac{45}{2}x-24$

probably don't have the dx set up right

Thank ahead for help