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- Thread starter pita0001
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- Jan 26, 2012

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Hmm, let's see if that works.I got -6, -10 using completing the square

\(\displaystyle (x+6)(x+10)=x^2+10x+6x+60=x^2+16x+60\)

That's not the same as the problem you posted. Is there a typo maybe?

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- Jan 26, 2012

- 4,055

That's not correct then. Can you show us your work?

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AsThe function is: f(x)= x^2+16x+62

I used completing the square method and my answers were -6 and -10.

Can you post your work so we can figure out where you went astray?

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\(\displaystyle a=1,\,b=16,\,c=62\)

and we have:

\(\displaystyle x=\frac{-16\pm\sqrt{16^2-4\cdot1\cdot62}}{2\cdot1}\)

Simplify:

\(\displaystyle x=\frac{-16\pm\sqrt{8}}{2}\)

Now, can you simplify further?

It looks like you are almost there...although you have omitted the $\pm$ sign. I really couldn't be sure what you were doing until I did it myself since you did not include bracketing symbols which leaves room for ambiguity.

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