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#### lfdahl

##### Well-known member

- Nov 26, 2013

- 719

If the last three digits of $n$ are removed, $\sqrt[3]{n}$ remains.

Find with proof $n$.

Source: Nordic Math. Contest

- Thread starter lfdahl
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- Thread starter
- #1

- Nov 26, 2013

- 719

If the last three digits of $n$ are removed, $\sqrt[3]{n}$ remains.

Find with proof $n$.

Source: Nordic Math. Contest

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- Feb 7, 2012

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If the last three digits of $n$ are removed, $\sqrt[3]{n}$ remains.

Find with proof $n$.

Source: Nordic Math. Contest

So $32\leqslant x<33$, and the only possible value for $x$ is $32$. Then $n = 32^3 = 32\,768$. When the last three digits are removed, what is left is $32$, as required.

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- Nov 26, 2013

- 719

Thankyou, Opalg , for an exemplary answer!

So $32\leqslant x<33$, and the only possible value for $x$ is $32$. Then $n = 32^3 = 32\,768$. When the last three digits are removed, what is left is $32$, as required.