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Find the unique solution

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anemone

MHB POTW Director
Staff member
Feb 14, 2012
3,690
Consider the 3 simultaneous equations

\(\displaystyle |x|-y-z=5\)

\(\displaystyle x-|y|+z=-9\)

\(\displaystyle x-y+|z|=-1\)

Find the unique solution of the simultaneous equation in which $x, y, z$ are all integers.
 

Jester

Well-known member
MHB Math Helper
Jan 26, 2012
183
My solution
Maybe not the most elegant but effective. Due to the presense of the absolutes we can consider 8 cases depending on whether $x, y$ and $z \ge 0$ or $< 0$. However we can rule out 6 of these immediately due to inconsistencies in the system. For example, if $x,y,z \ge 0$ the the system is

\begin{eqnarray}
x - y - 5 &=& 5\\
x-y+z &=& -9\\
x - y + z &=& -1
\end{eqnarray}

and clearly the last 2 equations are inconsistent. The only cases I found that were consistent where

\begin{eqnarray}
(i) & \;\;&x \ge 0,\;\;& y < 0,\;\; &z \ge 0\\
(ii)& \;\;&x <0.\;\; &y \ge 0,\;\;& z < 0
\end{eqnarray}

In each case, the systems were easily solved giving solutions $(-2.-4,-3)$ and $(-3,2,-4)$.
 

Klaas van Aarsen

MHB Seeker
Staff member
Mar 5, 2012
8,780
My solution
But you have 2 solutions, when surely there should only be one?! (Nerd)
Can you scratch the first one please?
(I selected the same method.)
 
Last edited:

Jester

Well-known member
MHB Math Helper
Jan 26, 2012
183
My solution
Maybe not the most elegant but effective. Due to the presense of the absolutes we can consider 8 cases depending on whether $x, y$ and $z \ge 0$ or $< 0$. However we can rule out 6 of these immediately due to inconsistencies in the system. For example, if $x,y,z \ge 0$ the the system is

\begin{eqnarray}
x - y - z &=& 5\\
x-y+z &=& -9\\
x - y + z &=& -1
\end{eqnarray}

and clearly the last 2 equations are inconsistent. The only cases I found that were consistent where

\begin{eqnarray}
(i) & \;\;&x \ge 0,\;\;& y < 0,\;\; &z \ge 0\\
(ii)& \;\;&x <0.\;\; &y \ge 0,\;\;& z < 0
\end{eqnarray}

In each case, the systems were easily solved giving solutions $(-2.-4,-3)$ and $(-3,2,-4)$.
As I like Serena pointed out, there is a unique solution. Clearly my first solution violates the condition $x \ge 0$ and $z \ge 0$.
 
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anemone

MHB POTW Director
Staff member
Feb 14, 2012
3,690
Hi Jester,

Thanks for participating and I think your method is quite elegant and I used the same concept to solve it too.

Hi I like Serena,

Thanks for everything!

But I have thought of another method to tackle the problem and the idea only hit me moment ago.

We're given to solve for the unique solution of the simultaneous equation below in which $x, y, z$ are all integers.

\(\displaystyle |x|-y-z=5\)---(1)

\(\displaystyle x-|y|+z=-9\)---(2)

\(\displaystyle x-y+|z|=-1\)---(3)

Adding the equations (1) and (2) givesAdding the equations (1) and (3) gives
Adding the equations (2) and (3) gives
\(\displaystyle |x|+x=|y|+y-4\)\(\displaystyle |x|-x=|z|+z+6\)\(\displaystyle |y|-y=z-|z|+8\)
Let $x<0$.

We then have

\(\displaystyle 0=|y|+y-4\)

This implies $y=2$.
When $y=2$, we have

\(\displaystyle 0=z-|z|+8\)

This gives $z=-4$.
When $x<0$, $y=2$, $z=-4$,

\(\displaystyle |x|-x=|z|+z+6\) becomes

\(\displaystyle -2x=6\)

$x=-3$
Now, we have to consider the case when $x>0$.

When $x>0$, we have

\(\displaystyle 0=|z|+z+6\)

And obviously the equation above has no solution and we're done! Yeah!(Sun)