Find the Two-Digit Number: Exceeds by 4 and 1 Less Than Twice the Units Digit

[paulmdrdo1]

The tens digit of a certain two-digit number exceeds the units digit by 4 and is 1 less than twice the units digit. Find the two-digit number.

this is my solution,

let $x=$ tens digit, $x-4=$units digit.

$x=2(x-4)-1$ then, $x=9$ and $9-4=5$

the number is 59

but when I let $x=$ units digit and $x+4=$ tens digit I get the answer of 95.

can you tell me which one is correct?

tnahks!

 

[MarkFL]

Re: digit problems.

I let $T$ be the tens digit and $U$ be the units digit, and so:

\(\displaystyle T=U+4=2U-1\implies U=5\implies T=9\)

And so the two digit number is $95$.

 

[Evgeny.Makarov]

Re: digit problems.

let $x=$ tens digit... $x=9$ and $9-4=5$

the number is 59

No, it's 95.

 

[Deveno]

Re: digit problems.

The tens digit of a certain two-digit number exceeds the units digit by 4 and is 1 less than twice the units digit. Find the two-digit number.

this is my solution,

let $x=$ tens digit, $x-4=$units digit.

$x=2(x-4)-1$ then, $x=9$ and $9-4=5$

the number is 59

but when I let $x=$ units digit and $x+4=$ tens digit I get the answer of 95.

can you tell me which one is correct?

tnahks!

In your solution you said: "let $x$ be the tens digit", and then solved for $x$ to obtain $x = 9$.

Thus your number is 9_ (ninety-something).

Solving for the unit digit, which you have as $x - 4$, you obtained: 5.

Thus your number is 95.

You solved it correctly, but misinterpreted your own solution.

 

[CellCoree]

I cannot determine which of the two answers is correct without more information. It appears that both solutions satisfy the given conditions, so either could be correct. It is possible that there is a typo in the problem or that there are multiple solutions. I would recommend double checking the problem or providing more context to determine the correct answer.