Find the total number of ways of coloring the eight regions

In summary, the discussion is about solving a problem related to graph theory using the deletion-contraction theorem or elementary counting. The participants also discuss the possibility that the OP may have already studied graph theory and the purpose of the question. The final solution involves the product of eight numbers, six of which are 2, and mirrors the deletion-contraction approach in reverse order.
  • #1
feesicksman
2
0
Homework Statement
We have a figure which has been divided into 8 regions (A to H) as shown below. Each region must be colored in exactly one color. There are four colors to choose from: yellow, red, green and blue. There is only one other constraint: neighboring regions must not be of the same color.
Find the total number of ways of coloring the regions A to H.
Relevant Equations
I think this problem can be viewed as a vertex coloring procedure (with at most 4 colors) in graph theory.
image.jpg

The eight regions
 
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  • #2
Please show your efforts to work on the problem. Thank you.
 
  • #3
It may help to first work through a smaller, simpler problem.
 
  • #4
If you know some graph theory, have you come across chromatic polynomials?
 
  • #5
OP has not returned. The solution can be found by elementary counting, I don't think that categorising the problem as graph theory helps.
 
  • #6
pbuk said:
The solution can be found by elementary counting,
Really? That looks a bit tough to me. Using the deletion-contraction theorem I got 768 quite quickly.
Besides, it would seem the OP has done some graph theory, so likely this question is intended as an exercise in using the theorem.
 
  • #7
haruspex said:
Really? That looks a bit tough to me. Using the deletion-contraction theorem I got 768 quite quickly.
I got the same answer accumulating the product of 8 numbers in my head, 6 of which are 2:
How many ways can you colour D? (d)
Given a colouring for D, how many ways can you colour E? (e, so what is de?)
Given a colouring for D and E, how many ways can you colour B? (b, so what is deb?)
...

haruspex said:
Besides, it would seem the OP has done some graph theory, so likely this question is intended as an exercise in using the theorem.
I'm not so sure - it could just be that they searched the interweb and found "vertex coloring procedure".

Anyway they don't look like they are interested in this any more.
 
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  • #8
pbuk said:
I got the same answer accumulating the product of 8 numbers in my head, 6 of which are 2:
How many ways can you colour D? (d)
Given a colouring for D, how many ways can you colour E? (e, so what is de?)
Given a colouring for D and E, how many ways can you colour B? (b, so what is deb?)
...
I'm not so sure - it could just be that they searched the interweb and found "vertex coloring procedure".

Anyway they don't look like they are interested in this any more.
Very neat. Interestingly, it mirrors the deletion-contraction approach, in reverse order.
To be looking up vertex colouring, the OP first had to recognise the duality between vertices and regions.
 

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