- #1
Richie Smash
- 293
- 15
Homework Statement
Hello, I havre problem here relevant to an image I will attach.
''A cricket ball hit by a batsman moves with a speed of 6m/s along a straight line path PQRS, as shown in the diagram. When the ball is at R, a fieldsman starts to run in a straight line from T with a speed of 10m/s.
Given that QRT = 25° and RT = 15m, determine by calculation or by drawing:
(a) the direction in which the fieldsman must run in order to retain the ball.
(b)the time he would take to reach the ball at s.
Homework Equations
V=distance/time
The Attempt at a Solution
I have absolutely no idea on this one I'm afraid.
The answer for part (a) in the backof the book is ''Bearing =79.7° ''
For (b), I drew a perpendicular line to QT. I then found angle RTQ which is 65°, then i worked out the angle from the perpendicular I drew by doing 90°-65° = 25°
From here i used the alternate angle rule to find angles RTS and RST which are 25°.
Then I found angle TRS which is 130° then used the sine rule to find side TS which I got to be 27.2 approx, then divided by 10 to find his speed, for which i got 2.72m/s.
Unfortunately that is also the wrong answer.