Find the speed of an electron accelerated through a potential difference

In summary, the formula used to calculate the speed of electrons striking the screen of a color television tube is E=mc^2/sqrt(1-v^2/c^2), with E representing the kinetic energy and rest energy of the electron. The correct conversion of 20,000 eV to MeV is 0.02 MeV. Using this formula, the resulting speed of the electrons is approximately 0.27c.
  • #1
Miri
36
0

Homework Statement


In a color television tube, electrons are accelerated through a potential difference of 20 000 volts. With what speed do the electrons strike the screen?
mass of electron=9.109*10^-31kg or 0.51099 MeV/c^2


Homework Equations


I don't know which formula I have to use. When I use E=mc^2/sqrt(1-v^2/c^2) I first have to add the kinetic energy (20 000eV) and the rest energy of the electron (0.51099MeV) and than solve for x (which is v^2/c^2). The solution should be 0.27c but I never get it...Thank you!
 
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  • #2
You have the right formula. Can you show your math? It sounds like there is a simple arithmetic error somewhere.

p.s. if instead you use the nonrelativistic expression for kinetic energy, the answer will not be very different.
 
  • #3
Ok. For E I use 20 000.51099MeV (KE+rest energy)
For mc^2 I use 0.51099MeV and for v^2/c^2 I use x because that's the thing I want to know. Then I put everything into the solver like this: solve(20000.51099=0.51099/sqrt(1-x^2),x) and my calculator says x is -1 or 1 (exact nr.: 0.99999999967363) I really don't know why I always get the wrong result...
 
  • #4
Okay. The kinetic energy is
KE = 20 000 eV 20 000 MeV​
 
  • #5
Thank you. But it doesn't change nothing when I use 20 000*10^6 eV + 0.51099MeV...Heeelp :S
 
  • #6
I think you need to double-check your conversion of 20,000 eV to MeV. 1,000,000 eV = 1 MeV
 
  • #7
The rest energy is .511MeV = 511,000eV

The kinetic is 20,000eV

You see how the kinetic energy is not larger than the rest energy? It is in fact smaller by about 25 times. This is why Redbelly said you can use non-relativistic mechanics because the kinetic energy is only a small fraction of the rest energy.

The way you have it now, your kinetic energy is 40,000 times larger than your rest energy...which is why you get an answer ridiculously close to c.
 
  • #8
Miri said:
Thank you. But it doesn't change nothing when I use 20 000*10^6 eV + 0.51099MeV...Heeelp :S

And it shouldn't change, because you are just repeating the same mistake.

20 000 eV is not, I repeat not, 20 000*106 eV.

To do the units conversion from eV to MeV:

20000 eV * (1 MeV/10^6 eV) = ____ ?
 
  • #9
oh yes..thank you very much..I forgot the minus: 20000*10^-6 eV=0.02MeV...Thank you for your patience :)
 

Related to Find the speed of an electron accelerated through a potential difference

What is the formula for finding the speed of an electron accelerated through a potential difference?

The formula for finding the speed of an electron accelerated through a potential difference is v = √(2qV/m), where v is the speed of the electron, q is the charge of the electron, V is the potential difference, and m is the mass of the electron.

What is potential difference?

Potential difference, also known as voltage, is a measure of the difference in electrical potential energy between two points in an electric field. It is typically measured in volts (V).

What is the unit of measurement for the speed of an electron?

The unit of measurement for the speed of an electron is meters per second (m/s).

How does the potential difference affect the speed of an electron?

The potential difference directly affects the speed of an electron. As the potential difference increases, the speed of the electron also increases, and vice versa. This is due to the fact that potential difference is directly proportional to the kinetic energy of the electron.

Why is it important to determine the speed of an electron accelerated through a potential difference?

Determining the speed of an electron accelerated through a potential difference is important in understanding the behavior and properties of electric fields. It is also crucial in the design and functioning of many electronic devices, such as computer processors and television displays.

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