- #1
ChrisWM
- 13
- 1
- Homework Statement
- Find the ratio of the energy of the La characteristic x-ray to the Ka characteristic x-ray for: a) Potassium b) Copper
- Relevant Equations
- 1/wavelength=R(z-1)^2*3/4
1/wavelength=R(z-7.4)^2*(1/4-1/n^2)
E=hc/wavelength
I found my energies for Potassium. I have 3.3 KeV for the k alpha nd 254.6 ev for L alpha, using z=19 and n=3. Are these values correct?
Edit: I found the ratio to be .077
Edit: I found the ratio to be .077