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rfig08d
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Homework Statement
The force exerted by the wind on the sails of a sailboat is 490 N north. The water exerts a force of 250 N east. If the boat (including its crew) has a mass of 250 kg, what are the magnitude and direction of its acceleration?
Homework Equations
V= SQRT(X2+Y2)
Tan-1(Vy/Vx)
The Attempt at a Solution
Drew it out on a piece of paper:
(0, 490N)
(250, 0)
So: (250, 490)
Direction = tan-1(490/250) = 62.96Magnitude = V = SQRT(490^2+250^2) = 550 = Wrong?
Why would the magnitude be incorrect? Or can anyone point out where I may be wrong?
Thank you!Edit - The answers are supposed to be in acceleration (m/s^2) and my magnitude came out to be:
550 Kg m/s^2 so I just divided by the kg and got my answer!
Silly mistake ;)
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