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Alexmahone
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- Jan 26, 2012
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Find $\displaystyle\lim_{n\to\infty}\frac{(2n)!!}{(2n-1)!!}$.
Is the answer $\displaystyle\lim_{n\to\infty} \frac{2}{1}\cdot\frac{4}{3}\cdot\frac{6}{5}\cdots \frac{2n}{2n-1}=\infty$?
Is the answer $\displaystyle\lim_{n\to\infty} \frac{2}{1}\cdot\frac{4}{3}\cdot\frac{6}{5}\cdots \frac{2n}{2n-1}=\infty$?
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