Find the Lagrangian of this single mass system

In summary: Momentum of the mass or object is not conserved?Yes, because the mass or object is constantly changing its velocity.
  • #1
MyoPhilosopher
41
4
Homework Statement
Find the lagrangian of the following system (pic included below)
Relevant Equations
L = T - U
1582971855522.png


1582971879118.png
 
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  • #2
Is there a question in this ?
 
  • #3
BvU said:
Is there a question in this ?
sorry, is my Langragian set up and equations correct?
 
  • #4
Did you check them thoroughly ? That should be enough, shouldn't it ?
 
  • #5
BvU said:
Did you check them thoroughly ? That should be enough, shouldn't it ?
Thanks for the help
 
  • #6
MyoPhilosopher said:
sorry, is my Langragian set up and equations correct?
What does it mean that the springs have zero equilibrium lengths?
What is the elastic potential energy?
 
  • #7
ehild said:
What does it mean that the springs have zero equilibrium lengths?
What is the elastic potential energy?
1. I understand it as that at the mass in the center of the blocks and at y=0 in my pic, and lengths L/2 for each spring, is 0 equilibrium
2. I have the two elastic PEs in the post above individually
 
  • #8
MyoPhilosopher said:
1. I understand it as that at the mass in the center of the blocks and at y=0 in my pic, and lengths L/2 for each spring, is 0 equilibrium
2. I have the two elastic PEs in the post above individually
Zero equilibrium length means zero length when the spring is unstretched. You assumed that the unstretched length is L.
What is the formula for the potential energy of a spring?
 
  • #9
Zero equilibrium length means spring energy is zero at spring length zero. Unrealistic, but pobably set like that to make it easier for you !
 
  • #10
ehild said:
Zero equilibrium length means zero length when the spring is unstretched. You assumed that the unstretched length is L.
What is the formula for the potential energy of a spring?
I assumed the unstreched length of each spring was L/2. 1/2 * k(Δx)^2
 
  • #11
BvU said:
Zero equilibrium length means spring energy is zero at spring length zero. Unrealistic, but pobably set like that to make it easier for you !
Alright so my equations for potential should quite literally use the (ΔLength = current length). so essentially 0.5k(0-currentl length)^2
 
  • #12
That is my interpretation, yes.
 
  • #13
Quesion: why did you choose the origin like that, instead of at the very center ?
 
  • #14
BvU said:
That is my interpretation, yes.
That makes sense thank you I misread and misunderstood that. Can I ask why the momentum of the mass or object is not conserved? Would be due to constantly changing velocities of the object?
 
  • #15
BvU said:
Quesion: why did you choose the origin like that, instead of at the very center ?
My first attempt was using polar coordinates but that did not work easily. I chose those points to get a clear x_dot and y_dot for my kinetic energy.
 

Related to Find the Lagrangian of this single mass system

1. What is the Lagrangian of a single mass system?

The Lagrangian of a single mass system is a mathematical function that describes the dynamics of the system in terms of its position and velocity. It is used in classical mechanics to derive the equations of motion for the system.

2. How is the Lagrangian of a single mass system calculated?

The Lagrangian of a single mass system is calculated by taking the difference between the kinetic energy and potential energy of the system. This can be expressed as L = T - V, where T is the kinetic energy and V is the potential energy.

3. Why is the Lagrangian of a single mass system useful?

The Lagrangian of a single mass system is useful because it simplifies the process of finding the equations of motion for the system. It allows for a more elegant and efficient approach to solving problems in classical mechanics.

4. Can the Lagrangian of a single mass system be used for any type of system?

Yes, the Lagrangian of a single mass system can be used for any type of system, as long as it can be described in terms of position and velocity. It is a general method that can be applied to a wide range of physical systems.

5. What are the advantages of using the Lagrangian over other methods in classical mechanics?

One of the main advantages of using the Lagrangian over other methods is that it takes into account all the forces acting on the system, rather than focusing on individual forces. This makes it particularly useful for systems with complex interactions between different components.

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