- #1
lioric
- 306
- 20
- Homework Statement
- Find the formula of a hydrocarbon. Combustion of that hydrocarbon resulted
in the formation of 2 L of carbon dioxide and 1.205 g of water. The relative density
of the hydrocarbon per helium is 13.5.
- Relevant Equations
- number of moles of any gas =22.4L
number of moles = mass/ molar mass
density = mass / volume
number of moles of CO2 =0.089moles (using 2/22.4)
number of moles of water = 0.067 (using 1.205/18)
I know that all the carbon from the hydrocarbon is in the CO2
and all the hydrogen from the hydrocarbon is in the water and water creates x2 hydrogens
so number of moles of C : H = 0.089 : 0.067x2
0.089 : 0.134
so I get 1 : 1.50
which is like 2 : 3
now what do I do with the relative density?
number of moles of water = 0.067 (using 1.205/18)
I know that all the carbon from the hydrocarbon is in the CO2
and all the hydrogen from the hydrocarbon is in the water and water creates x2 hydrogens
so number of moles of C : H = 0.089 : 0.067x2
0.089 : 0.134
so I get 1 : 1.50
which is like 2 : 3
now what do I do with the relative density?