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- Feb 14, 2012
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Find the exact value of the following definite integral:
\(\displaystyle \int_0^2 (3x^2-3x+1)\cos (x^3-3x^2+4x-2)\,dx\)
\(\displaystyle \int_0^2 (3x^2-3x+1)\cos (x^3-3x^2+4x-2)\,dx\)
I have a slightly different approach to Mark's...Find the exact value of the following definite integral:
\(\displaystyle \int_0^2 (3x^2-3x+1)\cos (x^3-3x^2+4x-2)\,dx\)