# Find the equation of the tangent line (Can someone check my work?)

#### shamieh

##### Active member
Find the equation of the tangent line to g(x) = arctan(x) + ln(x) @ x = 1

$$\displaystyle y - \frac{\pi}{4} = \frac{3}{2}(x - 1)$$

#### MarkFL

Staff member
Looks good to me.

#### Deveno

##### Well-known member
MHB Math Scholar
Find the equation of the tangent line to g(x) = arctan(x) + ln(x) @ x = 1

$$\displaystyle y - \frac{\pi}{4} = \frac{3}{2}(x - 1)$$
Your answer is indeed correct, but as no actual work is shown, we cannot verify that you didn't just happen to "guess" the right answer (although you probably didn't).

1) What is g'(x)?

2) What is the formula for the tangent line to g(x) at x = a?

The correct two answers to the questions I have listed above are actually more important than "the final answer".