peeyush_ali said:
The formula for finding the elongation of a spring of mass is F = kx, where F is the force applied to the spring, k is the spring constant, and x is the elongation of the spring.
The spring constant, denoted by k, is a measure of the stiffness of a spring. It is directly proportional to the elongation of a spring, meaning that the higher the spring constant, the greater the elongation of the spring for a given force applied.
Yes, the mass of an object can affect the elongation of a spring. According to Hooke's Law, the elongation of a spring is directly proportional to the force applied to it. Therefore, a heavier mass will cause a greater force on the spring, resulting in a larger elongation.
The units of measurement for the spring constant depend on the units used for force and elongation. If force is measured in newtons (N) and elongation in meters (m), then the unit for the spring constant is newtons per meter (N/m).
Yes, there is a limit to the elongation of a spring of mass. This is known as the elastic limit, beyond which the spring will permanently deform or break. The elastic limit varies depending on the type and quality of the spring.