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#### mitchconnor

##### New member

- Jun 7, 2013

- 2

f(x)=x−10−−−−−√x2+9x+8=x−10−−−−−√(x+8)(x+1)

Why does the x2+9x+8 become (x+8)(x+1)?

Thanks for the help!

- Thread starter mitchconnor
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- Thread starter
- #1

- Jun 7, 2013

- 2

f(x)=x−10−−−−−√x2+9x+8=x−10−−−−−√(x+8)(x+1)

Why does the x2+9x+8 become (x+8)(x+1)?

Thanks for the help!

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- #2

- Jan 26, 2012

- 4,197

I'm not entirely sure what mathematical operation is occurring between the $x-10$ and the $\sqrt{x^{2}+9x+8}$. Could you please clarify that for me?

f(x)=x−10−−−−−√x2+9x+8=x−10−−−−−√(x+8)(x+1)

Why does the x2+9x+8 become (x+8)(x+1)?

Thanks for the help!

As for $x^{2}+9x+8=(x+8)(x+1)$, that is a straight-forward factoring problem. If you multiply the RHS out, you will get the LHS.