- #1
rafay233
- 8
- 0
Homework Statement
A person is on a horizontal rotating platform at a distance of 4.3 m from its centre. This preson experiences a centripetal acceleration of 56m/s^2. What is the centripetal acceleration is experienced by another person who is at a distance of 2.5 m from the centre of the platform?
Homework Equations
?
The Attempt at a Solution
centripetal acceleration= [itex]\frac{v^2}{r}[/itex]
=5.6=[itex]\frac{v^2}{4.3}[/itex]
v=4.907m/scentripetal acceleration= [itex]\frac{v^2}{r}[/itex]
= [itex]\frac{4.9^2}{2.5}[/itex]
= 9.6m/s^2
I know that is not the right answer because it should be lower when closer to the center.
Last edited: