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Find the average force required to hold the gun in position

Joe_1234

New member
May 15, 2020
25
A gun fires 6 bullets per second into a target. The mass of each bullet is 3g & the speed of 500 m/s. Find the average force required to hold the gun in position.
 

skeeter

Well-known member
MHB Math Helper
Mar 1, 2012
705
Impulse equation ...

$F \cdot \Delta t = m \cdot \Delta v$
 

Joe_1234

New member
May 15, 2020
25

HallsofIvy

Well-known member
MHB Math Helper
Jan 29, 2012
1,151
You titled this "momentum" so it looks like you already knew the basic idea. The momentum of a single bullet is "mass times velocity" and you are given both of those. Of course, the momentum of 6 bullets is 6 times the momentum of a single bullet. Since this all happens in one second, divide by one second to get the force.

Be careful to use consistent units. You are given the mass in grams and the speed in m per second. Either convert mass to kg to get the force in Newtons or convert the speed to cm per second to get the force in dynes. I recommend the former.
 
Last edited:

skeeter

Well-known member
MHB Math Helper
Mar 1, 2012
705
You titled this "momentum" so it looks like you already knew the basic idea. The momentum of a single bullet is "mass times velocity" and you are given both of those. Of course, the momentum of 6 bullets is 6 times the momentum of a single bullet. Since this all happens in one second, divide by one second to get the force.
calculating the impulse for one bullet over $\Delta t = \frac{1}{6} \text{ sec}$ yields the same result as six bullets in $\Delta t = 1 \text{ sec}$
 

Jameson

Administrator
Staff member
Jan 26, 2012
4,043
Serious question - is it harder to type “thanks” or “tnx “ on your phone? On mine the latter will auto correct to something else so it’s actually harder.