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14) area of sector is πr²/3 = 12π

length of chord. that triangle has two sides of 6 and angle of 120º

split the triangle in two right triangles with angle of 120/2 = 60 and hyp=6. other (longer) side is:

sin 60 = x/6

s = 6 sin 60 = 6(√3/2) = 3√3

third side is

s = 3 cos 60 = 3

area =(1/2)(3)(3√3) = 4.5√3, double for both triangles

subtract that from the sector to get (12π) – (9√3)

15) similar to above.

find the area of the 270º sector and add the area of the triangle

area of sector is (270/360)(π9²) or (3/4)81π

area of triangle is (1/2)81

Is this correct?

What can i do differently?