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- #1

so right minus left so I know the first thing I need to do is

find the integrals

so

\(\displaystyle \frac{x^2}{8} + 1 = x - \frac{1}{2}\)

So I took a stab at this and got this..

\(\displaystyle \frac{x^2}{8} - \frac{8x}{8} + \frac{12}{8}\)

\(\displaystyle x^2 - 8x + 12 = (x - 6) (x - 2) = x = 6 x = 2\)

so

\(\displaystyle

\int^6_2 \frac{x^2}{8} + 1 - x - \frac{1}{2} dx\)

and I got \(\displaystyle \frac{128}{24}\) .. can someone check my work please? I'm skeptical of my process to get there.