- Thread starter
- #1
Albert
Well-known member
- Jan 25, 2013
- 1,225
find solutions of $x,y,z$
$\dfrac {1}{x}+\dfrac {1}{y+z}=\dfrac {1}{2}-----(1)$
$\dfrac {1}{y}+\dfrac {1}{z+x}=\dfrac {1}{3}-----(2)$
$\dfrac {1}{z}+\dfrac {1}{x+y}=\dfrac {1}{4}-----(3)$
$\dfrac {1}{x}+\dfrac {1}{y+z}=\dfrac {1}{2}-----(1)$
$\dfrac {1}{y}+\dfrac {1}{z+x}=\dfrac {1}{3}-----(2)$
$\dfrac {1}{z}+\dfrac {1}{x+y}=\dfrac {1}{4}-----(3)$