- #1
Denver Dang
- 148
- 1
Homework Statement
Hello...
Seems like an easy question, but I'm notquite sure though.
Find the oxidation number of platinum in the following compound:
Pt(NH3)2Cl(NO2)
Homework Equations
The Attempt at a Solution
If I just put Pt = x, and I know that (NH3) is neutral = 0, and Cl = -1, the one thing that is bothering me is the (NO2). If it was alone, you will know that N had oxidation number +4. But here it is in another compound. Usually O is -2 and N is -3, but that gives me a total of -7 for that, and with the Cl = -1, I have a total of +8 for Pt, which I'm pretty sure is incorrect.
What am I missing ? :)Regards