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#### kaliprasad

##### Well-known member

- Mar 31, 2013

- 1,331

Find all pairs of integers n and k such that $n!+8 = 2^k$

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- Mar 31, 2013

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Find all pairs of integers n and k such that $n!+8 = 2^k$

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- #2

- Mar 5, 2012

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From inspection I can find $n=4,\,k=5$.Find integers n and k such that $n!+8 = 2^k$

As a bonus I can see that $n=5,\,k=7$ works as well.

I kind of suspect that you intended to find all such integers, did you? Ah well, that was not the question.

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- Feb 7, 2012

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I really don't like that ISPOILER effect!From inspection I can find $n=4,\,k=5$.

As a bonus I can see that $n=5,\,k=7$ works as well.

I kind of suspect that you intended to find all such integers, did you? Ah well, that was not the question.

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- #4

- Mar 5, 2012

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It's new in Xenforo. I felt I just had to try it out.I really don't like that ISPOILER effect!

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- Mar 31, 2013

- 1,331

I have edited the question to make it more clearFrom inspection I can find $n=4,\,k=5$.

As a bonus I can see that $n=5,\,k=7$ works as well.

I kind of suspect that you intended to find all such integers, did you? Ah well, that was not the question.

your solution is correct. please mention the steps

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- Feb 7, 2012

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- #8

- Feb 7, 2012

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If you click on the blurred sections in the above comments, they will become clear and reveal the solutions.Where's the solutions?