Welcome to our community

Be a part of something great, join today!

Find max(n)

Albert

Well-known member
Jan 25, 2013
1,225
$n\in N$
$n^2 - 2112 $ is a multipler of $n+10$
please find :$max(n)$
 

kaliprasad

Well-known member
Mar 31, 2013
1,309
Re: Find max (n)

$n\in N$
$n^2 - 2112 $ is a multipler of $n+10$
please find :$max(n)$
n^2 - 2112 = n^2 - 100 - 2012

= (n+10)(n-10) - 2012

2012 is divisible by n+ 10 so max n = 2002