- Thread starter
- #1

#### Albert

##### Well-known member

- Jan 25, 2013

- 1,225

- Thread starter Albert
- Start date

- Thread starter
- #1

- Jan 25, 2013

- 1,225

- Mar 10, 2012

- 835

HINT:

Rotating the square by 90 degrees in the clockwise direction, the new position of $P$ is collinear with $P$ and $O$.

- Moderator
- #3

- Feb 7, 2012

- 2,786

Good idea! But what I would do is to rotate the square by 90 degrees in an

Rotating the square by 90 degrees in the clockwise direction, the new position of $P$ is collinear with $P$ and $O$.

- Thread starter
- #4

- Jan 25, 2013

- 1,225