- #1
Girn261
Homework Statement
A power plant operator on a bicycle is pedaling at uniform acceleration of "a", when his initial velocity "u" m/s. After 6.2s, and 9.3s, the bicycle had moved 23.5m & 39.7m respectively. Find the value of "u" & "a".
Homework Equations
s=ut+1/2at^2
The Attempt at a Solution
I have the solution, just have issues understanding it. Here is part of the solution.
23.5 = u6.2+1/2(a)(6.2^2) -> 23.5=u6.2+19.22a(9.3)
39.7= u9.3+1/2(a)(9.3^2) -> 39.7=u9.3+43.245a(6.2)
;
218.55=57.66u+178.746a
246.14=57.66u+268a
etc.
My question is, why is the 9.3 & 6.2 multiple added at the end of the equation in the beginning? That I can't seem to understand.