- #1
nirvana1990
- 46
- 0
If h(x)=(3x-5)/(7-2x)
Find an expression for h^-1(x)
Here's my attempt!
y=(3x-5)/(7-2x)
(swap x for y): x=(3y-5)/(7-2y)
I've tried rearranging to find y in terms of x but I can't see how to do it!
x(-2y)=(3y-5)/7
-2y=(3y-5)/7
-2y/3y=-5/x
Find an expression for h^-1(x)
Here's my attempt!
y=(3x-5)/(7-2x)
(swap x for y): x=(3y-5)/(7-2y)
I've tried rearranging to find y in terms of x but I can't see how to do it!
x(-2y)=(3y-5)/7
-2y=(3y-5)/7
-2y/3y=-5/x